5y^2+4.8y=0

Solution for 5y^2+4.8y=0 equation:

5y^2+4.8y=0

a = 5; b = 4.8; c = 0;
Δ = b2-4ac
Δ = 4.82-4·5·0
Δ = 23.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4.8)-\sqrt{23.04}}{2*5}=\frac{-4.8-\sqrt{23.04}}{10}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4.8)+\sqrt{23.04}}{2*5}=\frac{-4.8+\sqrt{23.04}}{10}
$